weight chart

lets say you have a 18 foot car and you have a 600 lb motor on the front how much weight would you be moveing to the front per every inch you move the motor to the front, is there any charts out there

 

Take the weight you want to move, subtract it by itself, divide by the axle to axle dimension in inches and multiply by one inch less than that.

Your example;
600lbs-600lbs / 216 inches x 215 inches = 2.77777 lbs/in

Rules to make this true;
1-216 inches must be the center of axle to center of axle dimension and in inches
2-the weights center of gravity must be inbetween the axle centerlines

Hope this helps.

 

Weight

SoDak, I just took the 18ft which is 216 inches and the 600 lbs divivded it and came up with the exact same thing (2.77) without all the extra numbers. What happened?


Corey

 

i figured it would be alot more than that i was going to move my motor a head 4or 5 inches to get more nose weight but for all i would gain would,nt be worth it

 

I guess I do things the hard way

 

This is a joke right ?
"Take the weight you want to move and subtract it by itself" = 0?Every time i try it...
I must need one uv dem dere fancy calkalators wit all duh gizmos und trinkits un it.

 

600-(600/216x215)=2.77 but technically you don't need to show the parentheses

or

just do it the easy way, 600/216=2.77

 

I am absolutely not saying you are wrong !
I find that formula interesting , Can it be that linear a change?

If that formula is correct, it seems that you would get a more substantial change in weight by making extreme moves to items in the car forward or back than by moving the engine an inch.

As an example if you had a 250" wheelbase car with 24lb battery directly over the front axle and you moved the battery to directly over the rear axle you made a 24lb chance. if you took that same 250" car with a 600lb engine you would have to move the engine back 10" to make the same weight change.

600/250=2.4 x10 = 24lbs

 

Yes, its linear.
You're examples are correct.